Answer:
240 grams of fat.
Explanation:
let
c = grams of carbohydrates
p =grams of proteins
f = grams of fat.
Then from the information given:
![4c+4p+9f=3800\:calories.](https://img.qammunity.org/2020/formulas/mathematics/high-school/b1ulpoq6rn0399pmfemrppl17br98lbqek.png)
And since 60% of the calories should come from carbohydrates and fats (which is 2280 calories)
![4c+9f =2280\:calories](https://img.qammunity.org/2020/formulas/mathematics/high-school/cvrl17j8ng38dp35ndtrbp9j5umofc5kru.png)
And
![c+p+f=650g.](https://img.qammunity.org/2020/formulas/mathematics/high-school/kyv9labt37uqa210lqn0vym6q8a04y833b.png)
Thus we have three equations:
(1).
![4c+4p+9f=3800\:calories.](https://img.qammunity.org/2020/formulas/mathematics/high-school/b1ulpoq6rn0399pmfemrppl17br98lbqek.png)
(2).
![4c+9f =2280\:calories](https://img.qammunity.org/2020/formulas/mathematics/high-school/cvrl17j8ng38dp35ndtrbp9j5umofc5kru.png)
(3).
![c+p+f=650g.](https://img.qammunity.org/2020/formulas/mathematics/high-school/kyv9labt37uqa210lqn0vym6q8a04y833b.png)
We put equation (2) into equation (1) and solve for
:
![2280+4p=3800](https://img.qammunity.org/2020/formulas/mathematics/high-school/fq847bnod7m058urlcl84x64dje2d4duam.png)
![\therefore \boxed{p =380\:grams}](https://img.qammunity.org/2020/formulas/mathematics/high-school/f3rufqtkr1bkoyj4rc0qimoxw5wbrdf2ly.png)
Now we put this value of
into equation (3) and get:
![c+f=270\:grams.](https://img.qammunity.org/2020/formulas/mathematics/high-school/y4o78a9zf3sstye2k6fu9k4lrw3dsvxaec.png)
Now from this equation we solve for c and get:
![c=270-f.](https://img.qammunity.org/2020/formulas/mathematics/high-school/kprrf34mxnyd1jx8rm3obdo6bnc8b88xxz.png)
And put this value of
into equation (2) and solve for
:
![4(270-f)+9f=2280.\\\\\therefore \boxed{f= 240 grams}](https://img.qammunity.org/2020/formulas/mathematics/high-school/8jkj8fz1yqpaq4on4g63zzjcnn6h8ol0s9.png)
Thus the diet will include 240 grams of fat.