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Complete the point slope equation of the line through (-5, 7) and (-4, 0).​

1 Answer

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For this case we have that by definition, the point-slope equation of a line is given by:


y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points:


(x_ {1}, y_ {1}): (- 5,7)\\(x_ {2}, y_ {2}): (- 4,0)

We found the slope:


m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} =  \frac {0-7} {- 4 - (- 5)} = \frac {-7} {-4 + 5} = \frac {-7} {1} = - 7

Thus, the equation is of the form:


y = -7x + b

We substitute one of the points and find "b":


0 = -7 (-4) + b\\0 = 28 + b\\b = -28

Finally, the equation is:


y = -7x-28

Answer:


y = -7x-28

User JChristian
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