Question

The length of a rectangle is eight more

Thon twice its width. The perimeter is 95
feet. Find the dimensions of the rectangle.
Variable
Equation:
Solution​

Answer 1

Width of the rectangle = 13.16 ft

Length of the rectangle = 34.33 ft

Explanation:

Let the width of the rectangle = k ft

So, the length of the rectangle = (2k + 8) ft

Perimeter of the rectangle = 95 ft

PERIMETER OF THE RECTANGLE = 2(LENGTH +WIDTH)

⇒ 2( k+ (2k+ 8)) = 95

or, 2( 3k + 8) = 95 ⇒ 6k + 16 = 95

or, 6k = 95 - 16 = 79

⇒ k = 79/ 6 = 13.16

So, the Width of the rectangle = k = 13.16 ft

Now, Length of the rectangle = 2(13.16)+ 8 = 34.33 ft