Answer:
The number of half-lives that have occurred are 4.
Step-by-step explanation:
Formula used for number of half lives :
![a=(a_o)/(2^n)](https://img.qammunity.org/2020/formulas/physics/middle-school/wc426m4m6wbvszw3jh4n9qa1af0njrxzxs.png)
where,
a = amount of reactant left after n-half lives
= Initial amount of the reactant
n = number of half lives
![a_o=x](https://img.qammunity.org/2020/formulas/physics/high-school/roejk5rzwckrxb65pt55xcc3zjmak7nv3p.png)
![a = x-(15)/(16)x=(1)/(16)x=a](https://img.qammunity.org/2020/formulas/physics/high-school/5zemrgkbccqyx3fs2wmtlfsocgcekp4xir.png)
![(1)/(16)x=(x)/(2^n)](https://img.qammunity.org/2020/formulas/physics/high-school/i5vg2a5wkgw5x51o72hiqdlor805f7z8yu.png)
n = 4
The number of half-lives that have occurred are 4.