Answer: 190
Split the summation into smaller summations that fit the summation rules
10∑ j=1 (2j+8) = 2 10∑ j=1 (j) + 10 ∑ j=1 (8)
Firstly Evaluate
10
2 ∑ j=1 j
The formula for the summation of a polynomial with degree one is:
n∑ k=1 k =n (n+1) / 2
putting the values
2∑ j=1 j = (2)* 10 * (10+1) / 2
= 110…………………..(1)
second Evaluate :
10 ∑ j=1 (8)
The formula for the summation of a constant is:
N ∑ k=1 c = cn
Putting the values
10 ∑ j=1 (8) = 8 * 10
= 80……………….(2)
Adding both (1) and (2)
110+80
190