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Four times the cube of a number is less than the difference between forty and the number. Select the inequality that represents this relationship.

(4x)3 < 40 - x

4x3 < x - 40

(4x)3 < x - 40

4x3 < 40 - x

User Bigwebguy
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2 Answers

6 votes

Answer:

Step-by-step explanation:

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than .

User Saurabh Deshpande
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2 votes

Answer:


4x^3 < 40 - x

Step-by-step explanation:

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by
x^3 is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as
x^3 is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than
x^3.

So, the inequality obtained can be written as
4x^3 < 40 - x

User Egal
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