Question

6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=

4
1
​
u, equals, start fraction, 1, divided by, 4, end fraction.

Answer 1

8

Explanation:

we have

`6t-20-32u`

Evaluate the expression for

t=6 and u=1/4

Substitute the value of t and the value of u in the expression above

`6(6)-20-32(1/4)`

`36-20-8`

`8`