Question

Sam measured the height of a window frame as 5.23 feet, but the actual height was 6 feet. What is the percentage of error in Sam's measurement?

Answer 1

12.83%

Explanation:

Answer 2

Answer: 12.83%

Explanation:

Given : Sam measured the height of a window frame as 5.23 feet, but the actual height was 6 feet.

i.e. Estimated height = 5.23 feet

Actual height = 6 feet

Then, the percentage of error in Sam's measurement will be :-

`\%\text{Error}=\frac{|\text{Estimated height-Actual height}|}{\text{Actual height}}*100\\\\=(|5.23-6|)/(6)*100\\\\ =(0.77)/(6)*100\\\\=12.8333333333\approx12.83\%`

Hence, the percentage of error in Sam's measurement= 12.83%