Question

marcus bikes 1000 meters from his home to the grocery in 2 mins the he bikes another 1000 meters back home in another 2.5 minutes what was the average speed in meters per second rounded to the nearest hundredth of marcus trip to and from the grocery store at

Answer 1

`{ \rm{average \: speed = (total \: distance)/(total \: time) }} \\ \\ = { \tt{ ((1000 * 2))/((2 + 2.5) * 60) }} \\ \\ = { \tt{ (2000)/(270) }} \\ \\ { \tt{average \: speed = 7.41 \: m {s}^( - 1) }}`