Question

Steam to drive an old-fashioned steam locomotive is supplied at a constant gauge pressure of 1.75×106N/m2 (about 250 psi) to a piston with a 0.200-m radius. (a) By calculating PΔV , find the work done by the steam when the piston moves 0.800 m. Note that this is the net work output, since gauge pressure is used.

Answer 1

Work done,
`W=1.75* 10^5\ J`

Step-by-step explanation:

It is given that,

Pressure of the stream,
`P=1.75* 10^6\ N/m^2`

Radius of the piston, r = 0.2 m

Distance moved by the piston, h = 0.8 m

Work done in terms of pressure is given by :

`W=P\Delta V`

`\Delta V` is the volume of cylinder

`W=P\Delta \pi r^2 h`

`W=1.75* 10^6* \pi 0.2^2* 0.8`

W = 175929.18 J

or

`W=1.75* 10^5\ J`

So, the work done by the stream is
`1.75* 10^5\ J`. Hence, this is the required solution.