Question

Nitrogen and hydrogen gas react to form ammonia gas as follows: N2(g) + 3H2(g) → 2NH3(g) At a certain temperature and pressure, 1.2 L of nitrogen gas reacts with 3.6 L of hydrogen gas. If all of the nitrogen and hydrogen is consumed, what volume of ammonia (at the same temperature and pressure) will be produced?

Answer 1

Given 1.2 L of nitrogen reacts with 3.6 L of hydrogen to produce ammonia, the volume of ammonia produced at the same conditions will be 2.4 L.

Step-by-step explanation:

When nitrogen (N₂) and hydrogen (H₂) gases react to form ammonia (NH₃), the reaction can be described using a balanced chemical equation: N₂(g) + 3H₂(g) → 2NH₃(g). The volumes of gases involved in this reaction at constant temperature and pressure are in the same ratio as the coefficients of the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia.

If 1.2 L of nitrogen gas reacts with 3.6 L of hydrogen gas, all of the nitrogen and hydrogen are consumed to form ammonia. Using the ratio from the balanced equation, we can calculate the volume of ammonia produced by doubling the volume of nitrogen gas that reacted. Therefore, the volume of ammonia gas produced will be 2.4 L (2 x 1.2 L = 2.4 L), assuming constant temperature and pressure.