Question

A car accelerates to the right from 12 m/s to 30 m/s in 6.0 s. What was its acceleration and displacement during this time interval

Answer 1

Acceleration = 3m/s^2

Displacement = 126 m

Step-by-step explanation:

The velocity changed from 12 to 30 m/s in 6 seconds. Using the formula for acceleration we get

(30-12)/6= 18/6= 3m/s^2

Displacement is d=.5a*t^2+v0*t

Inputting acceleration, time, and velocity leaves us with

d=1.5 * 36 + 12 * 6 = 54 + 72 = 126 m