Question

You have designed a treatment system for contaminant Z. The treatment system consists of a pipe that feeds into a CSTR. The pipe has a volume of 15 m3 and the CSTR has a volume of 60 m3 . The inflow is 10 m3 /d and the influent Z concentration is 2,500 mg/L. If the effluent from the CSTR has a Z concentration of 500 mg/L, what is the degradation

Answer 1

0.667 per day.

Step-by-step explanation:

Our values here are

`Q=10m^3/dV_p=15m^3\\V_(cstr)=60m^3\\c_p=2500mg/L\\c_(cstr)=500mg/L`

Degradation constant=k and is unknown.

We calculate the concentration through the formula,

`cc_(cstr) =(c_(in))/(1+K(V/Q)) \\cc_(cstr)=(c_p)/(1+K*(V_(csrt))/(Q))`

Replacing values we have

`1+k((60)/(10))=(2500)/(500)\\1+k=5\\K(6)=5-1\\K(6)=4\\K=2/3\\K=0.667/day`

That is the degradation constant of Z-contaminant