Answer:
62.56 g
Step-by-step explanation:
The reaction between calcium nitrate, Ca(NO₃)₂, and aluminum sulfate, Al₂(SO₄)₃, is:
3Ca(NO₃)₂ + Al₂(SO₄)₃ → 3CaSO₄ + 2Al(NO₃)₃
The molar masses are:
Ca(NO₃)₂ = 40 g/mol of Ca + 2*14 g/mol of N + 6*16 g/mol of O = 164 g/mol
Al₂(SO₄)₃ = 2*27 g/mol of Al + 3*32 g/mol of S + 12*16 g/mol of O = 342 g/mol
By the reaction stoichiometry:
3 moles of Ca(NO₃)₂ ---------------- 1 mol of Al₂(SO₄)₃
The mass is the number of moles multiplied by the molar mass, so:
3*164 of Ca(NO₃)₂ ------------------------ 1*342 of Al₂(SO₄)₃
492 g of Ca(NO₃)₂ --------------------- 342 of Al₂(SO₄)₃
90 g of Ca(NO₃)₂ --------------------- x
By a simple direct three rule:
492x = 30780
x = 62.56 g