Question

In a random sample of six microwave​ ovens, the mean repair cost was ​$80.00 and the standard deviation was ​$11.00. Assume the population is normally distributed and use a​ t-distribution to construct a 90% confidence interval for the population mean mμ. What is the margin of error of mμ​? Interpret the results.

Answer 1

E=14.1641

Explanation:

We have given that

`\bar{X} = 80 \\s= 13.5 \\n= 6`

Assuming a confidence interval of 95% for \mu we have that,

`\bar{X}-E< \mu < \bar{X}+E`

Where is Margin of error given by,

`E=t_c ((s)/(√(n)))`

For 95% in the T-Table we have that
`t_c = 2.57`, so

`E=2.57*((13.5)/(6)) = 14.1641`

So our Margin of error (E) is 14.1641