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In a large population, 91% of the households have cable tv. A simple random sample of 144 households is to be contacted and the sample proportion computed. What is the mean and standard deviation of the sampling distribution of the sample proportions?

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Answer with explanation:

We are given that
\hat{p}=0.91

Sample size :
n=144

The mean of the sampling distribution of the sample proportions is given by :-


\mu_{\hat{p}}=p=0.91

The mean of the sampling distribution of the sample proportions is 0.91

The standard deviation of the sampling distribution of the sample proportions :


\sigma_{\hat{p}}=\sqrt{(p(1-p))/(n)}\\\\=\sqrt{(0.91(1-0.91))/(144)}=0.0238484800354\approx0.0238

Hence, the standard deviation of the sampling distribution of the sample proportions is 0.0238

User Marc Litchfield
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