Answer:
Force of Friction = 1640 N
Coefficient of friction = 0.911
Step-by-step explanation:
forces act on the objects as shown in the graph.
Fx=Foroce of friction
T=tension of the thread
R=Normal Force(R=1800N)
μ= friction coefficient
a=acceleration =
![2ms^(-2)](https://img.qammunity.org/2020/formulas/physics/middle-school/oxilmu5i1g5qfis6iklbsoom299mm1i78k.png)
applying F=ma to 250kg object downwards
![F=m*a\\2500-T=250*2\\T=2000N](https://img.qammunity.org/2020/formulas/physics/middle-school/t2ol2ddpm1vx9sw31y38doqda8y9hub1z8.png)
applying F=ma to 180kg object rightwards
![F=m*a\\\\T-F_x=m*a\\2000-F_x=180*2\\F_x=1640N](https://img.qammunity.org/2020/formulas/physics/middle-school/d4abr94e249ffm3qbgxondtmii2t4v5eje.png)
According to Frictional Force Formula,
μ*R
1640=μ*1800
μ=0.911