Answer:
k is equal to 1
Explanation:
Since this is a geometric transformation called, translation, therefore the shifted function f'(x) is parallel to f(x), then the slope m=2 remains the same for f'(x). So f'(x)=2x -k. The shifting is five units to the right then, we have to subtract -5 to f(x)=2x+4, so:
![f'(x)=2x-k\Rightarrow f'(x)=2x+(4-5)\Rightarrow f'(x)=2x-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3q1kltyvaoib7ng2tsbbooubdy90h4mpju.png)
Proving the 5 units shifting
f(x)=2x+4
x| y
1 | 6
2|8
f'(x)=2x-1
x|y
1| 1
2|3
Notice that every number ∈ to the Range of f(x) has a difference of 5 units when compared to f'(x) Range values.
6-1=5
8-3=5