Answer:
The slop of line perpendicular to line y =
x - 2 is ( - 3)
Explanation:
Given Line equation as ,
y =
x - 2
The equation of line is y = mx + c
Slop of this line (m1) =
![(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o08xg954t1gbzo9avralvfomcybk63rm02.png)
Now second line with slop (m2) is perpendicular to line first , then
(m1) × (m2) = - 1
So, (m2) =
![(-1)/(m1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/31vzf5j7cmtu8iepzvwhwrjye0mh6xea0j.png)
Or , (m2) =
![(-1)/((1)/(3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ndf64z62ne7g21gbqbje6ujt66y4z6cr2g.png)
∴ (m2) = - 3
Hence the slop of line perpendicular to line y =
x - 2 is ( - 3) Answer