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18. What is the slope of a line perpendicular to y=1/3x - 2

1 Answer

3 votes

Answer:

The slop of line perpendicular to line y =
(1)/(3) x - 2 is ( - 3)

Explanation:

Given Line equation as ,

y =
(1)/(3) x - 2

The equation of line is y = mx + c

Slop of this line (m1) =
(1)/(3)

Now second line with slop (m2) is perpendicular to line first , then

(m1) × (m2) = - 1

So, (m2) =
(-1)/(m1)

Or , (m2) =
(-1)/((1)/(3))

(m2) = - 3

Hence the slop of line perpendicular to line y =
(1)/(3) x - 2 is ( - 3) Answer

User Viraj Parekh
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