Question

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Find the equation of a line given the point and
the constant
(-6, 1)
m =6

Answer 1

The equation of the line is y=6x+37

Explanation:

You can write the equation using the slope intercept form techniques which is y=mx+c where m is the slope of the line and cis they intercept constant.

Given the point (-6,1) and slope m=6then

Δy/Δx =m

`y-1/x--6 = 6\\\\y-1/x+6=6\\\\\\y-1=6(x+6)\\\\\\y-1=6x+36\\\\\\y=6x+36+1\\\\y=6x+37`