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A charge enters a uniform magnetic field oriented perpendicular to its path. The field deflects the particle into a circular arc of radius R. If the charged particle enters the same magnetic field with three times the speed, what will be the radius of the circular arc?

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Answer:

The new radius is three times the initial radius

Step-by-step explanation:

The magnetic force is given by the equation

F = q v x B

Where the blacks indicate vectors, q is the electric charge, v the velocity of the particle and B the magnetic field. The scalar magnitude of this force is

F = q v B sin θ

Where θ is the angle between the velocity and the magnetic field.

As the force is perpendicular to the velocity, the particle describes a circular motion, using Newton's second law we can find the acceleration that is centripetal.

F = ma

a = v² / r

q v B = mv² / r

R = mv / qB

Let's calculate for the new speed (v₂ = 3v)

R₂ = (m / qB) 3v

R₂ = 3 R

R₂ / R = 3

The new radius is three times the initial radius

User Marcos Nunes
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