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How fast must a 1.88-9 ping-pong ball move (in m/s) in order to have the same kinetic energy as a 230.5 g baseball moving

58.5 m/s?

1 Answer

4 votes

Step-by-step explanation:

KE = KE

½ mv² = ½ mv²

½ (1.88 g) v² = ½ (230.5 g) (58.5 m/s)²

v = 648 m/s

User Glexey
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