Question

A sonar pulse is sent from one submarine to another submarine, where it is reflected and returned. If the round trip takes 6 seconds, how far away is the other submarine? (Assume the bulk modulus for seawater is 2.1 x 109 Pa and its density is 1030 kg/m3)

Answer 1

4283.64 m away

Step-by-step explanation:

`\beta` = Bulk modulus

`\rho` = Density

Speed of sound in a material is given by

`v=\sqrt{(\beta)/(\rho)}\\\Rightarrow v=\sqrt{(2.1* 10^9)/(1030)}\\\Rightarrow v=1427.88\ m/s`

If the round trip takes 6 seconds then the one way trip wil take 3 seconds

Distance = Speed × Time

`Distance=1427.88* 3=4283.64\ m`

So, the other submarine is 4283.64 m away