Question

Find the 16 term in sequence a(n) = -6+3(n-1)

Answer 1

39. A(16) = -6 + 3(16-1) = -6 + 45 = 39.

Answer 2

16th term in sequence a(n) = -6+ (n-1) 3 is 39.

Solution:

Need to determine 16 terms in sequence.

a(n) = -6+3(n-1) that is
`a_n` = -6+ (n-1) 3

from given expression we can say that first term
`a_1` = -6 and common difference d = 3

And given expression
`a_n` = -6+ (n-1) 3 represents formula of nth term of an Arithmetic Sequence.

So substituting n = 16 in given formula we get

`a_(16)` = -6+ (16-1) 3

=>
`a_(16)` = -6 + (15 x 3)

=>
`a_(16)` = -6 + 45

=>
`a_(16)` = 39

Hence 16th term in sequence
`a_n` = -6+ (n-1) 3 is 39.