For this case we have the following functions:
![g (x) = 15-4x\\h (x) = x + 8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h2ptbofrzobumo8811s10iqw9ckwbx13ts.png)
We must find
when
.
So:
![g (h (x)) = 15-4 (x + 8) =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3bd2bvqfdawq2s25ztpc8xrb5bxq19g8hq.png)
We apply distributive property to the terms within parentheses taking into account that:
![- * + = -\\15-4x-32 =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/99w8r4iw50gjs9kd4tz6wwgj0okgcsh9pl.png)
We add similar terms taking into account that different signs are subtracted and the sign of the major is placed:
![-17-4x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sxzsc621x3337cz2rk0dj72o1xcrpe8f27.png)
Thus, we have to:
![g (h (x)) = - 17-4x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gkotp6mazppxvds9q9005of06fskrnmkiv.png)
Then, with x = 2:
![g (h (2)) = - 17-4 (2) = - 17-8 = -25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wt7x83b354ss6rjb35bqe57vlsxrb5pf5b.png)
Equal signs are added and the same sign is placed.
Answer:
![g (h (2)) = - 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kom0mxlg9sw55r49gxv2nz4rpuwcv0znzs.png)