103k views
4 votes
Consider the following balanced equation CaC2(s) + 2H2O(I) → Ca(OH)2(s) + C2H2(g)

When 1.50 mol of CaC2 are allowed to react, how many moles of Ca(OH)2 is
produced?​

User Pzed
by
6.1k points

1 Answer

4 votes

Answer:

1.50 moles of CaC₂ will produced 1.50 moles of Ca(OH)₂ .

Step-by-step explanation:

Given data:

Moles of CaC₂ = 1.50 mol

Moles of Ca(OH)₂ = ?

Solution:

First of all we will write the balanced chemical equation.

CaC₂ + 2H₂O → Ca(OH)₂ + C₂H₂

Now we will compare the moles of CaC₂ with Ca(OH)₂ from balanced chemical equation.

CaC₂ : Ca(OH)₂

1 : 1

1.50 : 1.50

1.50 moles of CaC₂ will produced 1.50 moles of Ca(OH)₂ .

User Hjelpmig
by
6.3k points