524,342 views
7 votes
7 votes
The sum of two consecutive odd integers is at most 100. Find the pair with the greatest sum.

User Elias Schoof
by
3.0k points

2 Answers

15 votes
15 votes

We are given that the sum of the two consecutive odd integers is at most 100, so we can write:

x + (x+2) ≤ 100

Simplifying the above inequality, we get:

2x + 2 ≤ 100

2x ≤ 98

x ≤ 49

Since x is an odd integer, the largest possible value of x is 49. Therefore, the two consecutive odd integers are 49 and 51, and their sum is 100, which is the maximum possible sum of two consecutive odd integers that satisfy the given condition.

Hence, the pair of consecutive odd integers with the greatest sum is (49, 51).

IG:whis.sama_ent

User Rcgldr
by
2.8k points
21 votes
21 votes

Answer: 49, 51

Explanation:

x=odd integer number one.

x+(x+2)=100

x+x+2=100

2x+2=100

2x=98

x=49

x+2=49+2=51

49, 51

User Sam Keays
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.