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Lamar writes several equations trying to better understand potential energy. H = d with an arrow to the equation W = F d and P E Subscript g Baseline = m g h. F Subscript g Baseline = mg with arrows to the F in W = F d and to P E Subscript g Baseline = m g h. What conclusion is best supported by Lamar's work? The elastic potential energy is the same for any distance from a reference point. The gravitational potential energy equals the work needed to lift the object. The gravitational potential energy is the same for any distance from a reference point. The elastic potential energy equals the work needed to stretch the object.

2 Answers

5 votes

Answer:

The correct answer is B.

B. The gravitational potential energy equals the work needed to lift the object.

Step-by-step explanation:

it is correct

User Picklepick
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Answer:

The gravitational potential energy equals the work needed to lift the object.

Step-by-step explanation:

here we know that


H = \vec d

work done is given as


W = \vec F . \vec d

Potential energy is given as


PE_g = mgh

force due to gravity is given as


\vec F_g = mg

now here if we plug in the value of distance and force in the formula of work done then we will have


W = (mg)(h)

so here we got


W = PE_g

so we can concluded that

The gravitational potential energy equals the work needed to lift the object.

User Nisanth Sojan
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