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Find the coefficients of the terms below in the expansion of (uu+vv)8. Explain your reasoning.

a. u2v6
b. u3v5
c. u4v4

1 Answer

3 votes

Answer:

Remember, the expansion of
(u+v)^n=\sum_(k=0)^n\binom{n}{k}u^(n-k)v^k.

Then,


(u+v)^8=\sum_(k=0)^8\binom{8}{k}u^(8-k)v^k

a) since
u^(8-k)=u^2, then
8-k=2, k=6. Therefore, the coefficient of
u^2v^6 is
\binom{8}{6}=28

b)
u^3v^5=u^(8-k)v^k. Then k=5 and the coefficient of the term is
\binom{8}{5}=56

c)
u^4v^4, then k=4 and the coefficient of the term is
\binom{8}{4}=70

User Rajesh Nagpal
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