Answer:
![9.6\cdot 10^(-18) A](https://img.qammunity.org/2020/formulas/physics/middle-school/a0y70k95ciqhf8n9uxxbi9san6m55lf70d.png)
Step-by-step explanation:
Current is defined as
![I=(Q)/(t)](https://img.qammunity.org/2020/formulas/physics/high-school/8jq49ks0b4i0ittgbn7o8x7ds4lc33m7gs.png)
where
Q is the charge passing through a given point
t is the time interval
The SI unit of the current is the Ampere (A), where
![1A = 1C/s](https://img.qammunity.org/2020/formulas/physics/middle-school/3cf6yn3b34blqucjp7iczz516nshyrtcjt.png)
which means 1 Ampere is 1 Coulomb per second.
The charge of 1 electron is (in magnitude)
![e=1.6\cdot 10^(-19)C](https://img.qammunity.org/2020/formulas/physics/high-school/98ae3qhks63zozpyndu35mauu82gajjadg.png)
So, the charge of 60 electrons is
![Q=Ne=(60)(1.6\cdot 10^(-19))=9.6\cdot 10^(-18) C](https://img.qammunity.org/2020/formulas/physics/middle-school/vx0mjywex7y2v69hp0o5mfh3q84qzwuyk4.png)
Therefore, if there are 60 electrons passing per second, the current is
![I=(9.6\cdot 10^(-18) C)/(1 s)=9.6\cdot 10^(-18) A](https://img.qammunity.org/2020/formulas/physics/middle-school/mvc4x0xvncrp4uym1vg359nouyw270zuv2.png)