Final answer:
The energy of a photon with a frequency of 6.75 × 10^12 s^-1 is approximately 4.47 × 10^-21 joules, calculated using the formula E = hf with Planck's constant.
Step-by-step explanation:
The energy of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 × 10-34 J·s), and f is the frequency of the photon. In this case, to calculate the energy of a photon with a frequency of 6.75 × 1012 s-1, we can plug the given values into the formula:
E = h·f = (6.626 × 10-34 J·s) × (6.75 × 1012 Hz) = 4.47225 × 10-21 J.
Therefore, the energy of the photon is approximately 4.47 × 10-21 joules.