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calculate the energy of a photon of electromagnetic radiation his frequency is 6.75×10 to the 12 power S to the -1 power

User Bonkles
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2 Answers

5 votes

Final answer:

The energy of a photon with a frequency of 6.75 × 10^12 s^-1 is approximately 4.47 × 10^-21 joules, calculated using the formula E = hf with Planck's constant.

Step-by-step explanation:

The energy of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 × 10-34 J·s), and f is the frequency of the photon. In this case, to calculate the energy of a photon with a frequency of 6.75 × 1012 s-1, we can plug the given values into the formula:

E = h·f = (6.626 × 10-34 J·s) × (6.75 × 1012 Hz) = 4.47225 × 10-21 J.

Therefore, the energy of the photon is approximately 4.47 × 10-21 joules.

User Teron
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5.0k points
3 votes

Answer:

4.47 × 10^-21 Joules

Step-by-step explanation:

We are given the frequency of the wave as 6.75 × 10^12 Hz

  • Electromagnetic radiations are radiations that do not require a material medium for transmission and travel with a speed of light.
  • Each photon of electromagnetic radiation posses energy.
  • Energy of a photon is calculated by multiplying frequency of the photon by the plank's constant.

That is, E = hf

The plank's constant = 6.626 × 10^-34 J-s

Thus;

Energy = (6.626 × 10^-34 J-s × 6.75 × 10^12 Hz)

= 4.47 × 10^-21 Joules

Hence, the energy of the photon is 4.47 × 10^-21 Joules

User Efrem
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