Question

The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.

What is the constant of the quadratic expression in this equation?

x2 + x + _ = 0

Answer 1

-420

Explanation:

Answer 2

-420

Explanation:

Let x be the smaller of two consecutive integers. Then the larger of these two integers is x + 1.

The product of these two integers is

`x(x+1)=x^2+x`

The product of two consecutive integers is 420, so

`x^2+x=420\\ \\x^2+x-420=0`

The constant of the quadratice equation is -420.