Answer:
A. 94
Explanation:
The nth term of an arithmetic sequence is:
an = a₁ + d (n − 1)
where a₁ is the first term,
and d is the common difference.
We're told the first term is 40, and the 7th term is 121. Therefore:
121 = 40 + d (7 − 1)
121 = 40 + 6d
81 = 6d
d = 13.5
So the fifth term is:
a₅ = 40 + 13.5 (5 − 1)
a₅ = 40 + 54
a₅ = 94