Question

The temperature of a heat engine is 500 K. Some of the heat generated by the engine flows to the surroundings, which are

at a temperature of 125 K.
The efficiency of the engine is

Answer 1

75%

Step-by-step explanation:

Answer 2

The efficiency of the engine is 75% under given conditions.

Explanation:

Efficiency is defined as the ratio of work done by the engine to the total heat supplied to a heat engine. We know work done by the heat engine be difference between total heat supplied
`\left(Q_(h)\right)` by total heat utilized
`\left(Q_(c)\right)`. We can derive formula for efficiency by considering the above factors,
`\text { efficiency }=\frac{\text { work done }}{\text { heat suplied }}=(Q_(h)-Q_(c))/(Q_(h))=1-(Q_(c))/(Q_(h))=1-(T_(1))/(T_(2)) \therefore \text { efficiency }=1-(T_(1))/(T_(2))`

Now consider a heat engine is at a temperature of 500K and the heat produced by the engine released to the surroundings at a temperature of 125K. The efficiency is calculated by using the above formula,
`\text { efficiency }=1-(T_(1))/(T_(2))=1-(125)/(500)=1-0.25=0.75`

∴ Efficiency of the engine is 75%