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The dimensions of a closed rectangular box are measured as 97 cm, 67 cm, and 34 cm, respectively, with a possible error of 0.2 cm in each dimension. Use differentials to estimate the maximum error in calculating the surface area of the box. (Round your answer to one decimal place.)

User KodeTitan
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3 votes

Answer:

The maximum error in calculating the surface area of the box is
158.4 \:cm^2.

Explanation:

Differentials are infinitely small quantities. Given a function
y=f(x) we call
dy and
dx differentials and the relationship between them is given by,


dy=f'(x) \:dx

If the dimensions of the box are
l,
w and
h, its surface area is
A=2(wl+hl+hw) and


dA=(\partial A)/(\partial l)dl+(\partial A)/(\partial w)dw+(\partial A)/(\partial h)dh\\\\dA=2(w+h)dl+2(h+l)dw+2(w+l)dh

We are given that
|\Delta l|\leq 0.2,
|\Delta w|\leq 0.2, and
|\Delta h|\leq 0.2.

To find the largest error in the surface area, we therefore use
dl=0.2, dw=0.2, dh=0.2 together with
l=97, w=67,h=34


dA=2(w+h)dl+2(h+l)dw+2(w+l)dh\\\\dA=2(67+34)\cdot 0.2+2(34+97)\cdot 0.2+2(67+97)\cdot 0.2\\\\dA=158.4 \:cm^2

An error of 0.2 cm in each dimension could lead to an error of
158.4 \:cm^2 in the calculated surface area.

User Okpara
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