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A train 471 m long is moving on a straight track with a speed of 75.1 km/h. The engineer applies the brakes at a crossing, and later the last car passes the crossing with a speed of 15 km/h. Assuming constant acceleration, determine how long the train blocked the crossing. Disregard the width of the crossing. Answer in units of s.

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Answer:


t = 37.6 s

Step-by-step explanation:

As we know that train is initially moving with the speed


v_i = 75.1 km/h

now we know that


v_i = 20.86 m/s

now the final speed of the train when it crossed the crossing


v_f = 15 km/h


v_f = 4.17 m/s

now we can use kinematics here


v_f^2 - v_i^2 = 2 a d


4.17^2 - 20.86^2 = 2 a(471)


a = -0.44 m/s^2

Now the time to cross that junction is given as


v_f - v_i = at


4.17 - 20.86 = a(-0.44)


t = 37.6 s

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