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What is the approximate length of the hypotenuse of a right triangle with vertices (-6, 2),

(6,-3) and (-6, -3)?​

User Jag
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1 Answer

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Answer:

Explanation:

A(-6, 2), B(6,-3) and C(-6, -3)

AB² = (x₂ - x₁)² + (y₂ - y₁)²

= ( 6 -[-6])² + ( -3 -2)²

= ( 6 + 6)² + ( -3 -2)² = 12² + (-5)² = 144 + 25 =169

AB = √169 = 13 units

BC² = ( -6 -6)² + ( -3 - [-3])² = (-6-6)² + (-3 +3)²

= (-12)² + 0 = 144

BC = √144 = 12 unis

CA² = (-6 - [-6])² +(-3-2)² = (-6 + 6)² + ( -3-2)²

= 0 + (-5)² = 25

CA =√25 = 5 units

length of the hypotenuse of a right triangle = 13units

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