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A stream of water strikes a stationary turbine blade horizontally as the drawing illustrates The incident water stream has a velocity of 4 m s while the exiting water stream has a velocity of 4 m s The mass of water per second that strikes the blade is 31 kg s Find the magnitude of the average force exerted on the water by the blade

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Answer: 248 Newton

Step-by-step explanation:

force = rate of change of momentum

change of velocity

= 4 + 4 = 8 m/s



rate of change of momentum = mass per second x change of velocity



= 31 kg/s x 8 m/s 

= 248 kg m/s^2 or Newtons

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