Answer:1) x =19
y = -13
z = 2
2) x= 1
y= 1
z = 0
Explanation:
1)
-x-y-z=-8--------1
-2x-y+z=-3 --------2
2x+3y+3z=5--------3
From eqn 1,
x= 8 - y-z
Put x in eqn 2 and 3
- 2(8-y-z) - y +z = -3
-16+2y+2z-y+z = -3
y+ 3z = 13 -----4
2(8-y-z)+3y+3z=5
16-2y-2z+3y +3z = 5
y+z=-11 -------5
Using elimination method for eqn 4 and 5
2z = 24
z = 2
y = -11-2 = -13
Put x and y into eqn 1
x = 8- -13-2 =19
2)
-2x+2y+3z=0--------1
-2x-y+z=-3-------------2
2x+3y+3z=5-----------3
Subtract eqn 2 from eqn 1
2y - -y +2z = -3
3y +2z = 3----------4
Add eqn 2 and eqn 3
2y +4z = 2---------5
Multiply eqn 4 by 2 and eqn 5 by 3
6y + 4z =6 --------6
6y + 12z = 6-------7
Subtract eqn 7 from eqn 6
-8z = 0
z = 0
2y +4z = 2
2y + 4*0=2
2y = 2
y = 1
Putting y = 1 and z = 0 in eqn 1
-2x+2*1+3*0=0
-2x + 2+ 0 = 0
-2x = -2
x = 1