Question

X^2 - 10x + 13 = 0

Solve quadratic equation
In simplest form

Answer 1

`5 \pm 2√(3)`

Explanation:

A quadratic equation in the form

`ax^2+bx+c=0`

Can be solved by using the formula

`x=(-b\pm √(b^2-4ac))/(2a)`

In this problem, the equation is

`x^2-10x+13=0`

So, we have

a = 1

b = -10

c = +13

Using the equation above, we find:

`x=(-(-10)\pm √((-10)^2-4(1)(13)))/(2(1))=(10 \pm √(48))/(2)=(10 \pm 4√(3))/(2)= 5 \pm 2√(3)`