Question

A researcher studying the nutritional value of a new candy places a 4.90 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.08 ∘C. If the heat capacity of the calorimeter is 33.50 kJ⋅K−1, how many nutritional Calories are there per gram of the candy?

Answer 1

449730.879 cal/g

Step-by-step explanation:

Given data:

Mass of sample = 4.9 g

Change in temperature = 2.08 °C (275.23 k)

Heat capacity of calorimeter = 33.50 KJ . K⁻¹

Solution:

C(candy) = Q/m

Q = C (calorimeter) × ΔT

C(candy) = C (calorimeter) × ΔT / m

C(candy) = 33.50 KJ . K⁻¹ × 275.23 K / 4.90 g

C(candy) = 9220.205 KJ / 4.90 g

C(candy) = 1881.674 KJ / g

It is known that,

1 KJ /g = 239.006 cal/g

1881.674 × 239.006 = 449730.879 cal/g