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A 50.0-g ball traveling at 25.0 m/s bounces off a brick wall and

rebounds at 22.0 m/s. A high-speed camera records this event. If the
ball is in contact with the wall for 3.50 ms, what is the magnitude of
the average acceleration of the ball during this time interval?

1 Answer

5 votes

Answer:

13,400 m/s²

Step-by-step explanation:

Average acceleration is the change in velocity over time:

a = Δv / t

a = (22.0 m/s − (-25.0 m/s)) / 0.00350 s

a = 13,400 m/s²

User Sune Rasmussen
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