Question

What is the force on a 1000 kg elevator that is falling freely at 9.8m/s2

Answer 1

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8m s2 = 9800N To draw a Free Body Diagram, draw an elevator cage (I am sure you would get lots of points for drawing it with intricate detail) with a downward force of 9800 N. I hope this helps,

Step-by-step explanation:

Answer 2

Step-by-step explanation:

❀
`\underline {{\underline{ \text{Given} }}}:`

• Mass ( m ) = 1000 kg
• Acceleration ( a ) = 9.8 m/s²

❀
`\underline{ \underline{ \text{To \: find}}} :`

• Force ( F )

❀
`\underline{ \underline{ \text{Solution}}} :`

`\boxed{ \sf{force = mass * acceleration}}`

Plug the known values :

⟶
`\sf{1000 * 9.8}`

⟶
`\sf{9800 \: N}`

`\red{\boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 9800 \: N}}}}`

Hope I helped !♡

Have a wonderful day / night ! ツ

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