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2 votes
Y = mx + b to find the equation of the line that passes through the points (−6, 1) and (3, 4).

y = –3x + 5

y = 3x – 5

User Matt Coady
by
5.9k points

2 Answers

2 votes

Answer:

Answer:

Explanation:

we know that

The equation of the line in slope intercept form is equal to

where

m is the slope

b is the y-coordinate of the y-intercept

we have the points

(−6, 1) and (3, 4)

substitute the value of x and the value of y of each point in the equation of the line, then solve for m and b

For (-6,1)

-----> -----> equation A

For (3,4)

----> -----> equation B

Solve the system of equations A and B

Match equation A and equation B

Solve for m

Find the value of b

The equation of the line is

Explanation:

User Dactyrafficle
by
5.3k points
4 votes

Answer:


y=(1)/(3)x+3

Explanation:

we know that

The equation of the line in slope intercept form is equal to


y=mx+b

where

m is the slope

b is the y-coordinate of the y-intercept

we have the points

(−6, 1) and (3, 4)

substitute the value of x and the value of y of each point in the equation of the line, then solve for m and b

For (-6,1)


1=-6m+b ----->
b=6m+1 -----> equation A

For (3,4)


4=3m+b ---->
b=-3m+4 -----> equation B

Solve the system of equations A and B

Match equation A and equation B


6m+1=-3m+4

Solve for m


6m+3m=4-1


9m=3


m=(1)/(3)

Find the value of b


b=6((1)/(3))+1


b=3

The equation of the line is


y=(1)/(3)x+3

User Abdulbasit
by
4.9k points
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