Question

H+j + 2k = 16
4h + 4j + 2k = 5
2h + 2j + k = 31​

Answer 1

Answer and explanation:

h

Subtract h + j + 2k = 16 by 4h + 4j + 2k = 5

h + j + 2k = 16

-(4h + 4j + 2k = 5)

-3h - 3j = 11 Then add 3j to both sides to get -3h alone

-3h = 11 + 3j Now divide both sides by -3 to get h

h =
`(11 + 3j)/(-3)` =
`-(11)/(3) - j`

j

Plug in h and k to h + j + 2k = 16 --->
`-(11)/(3) - j` + j + 2(1) = 16

Then add any like terms together
`-(11)/(3) + (6)/(3)` + 2j = 16

Add
`-(5)/(3)` on both sides 2j =
`(5)/(3)` + 16

Divide both sides by 2
`(2j)/(2) = ((5)/(3))/(2)`

You can divide a fraction by a fraction, so you do kcf j =
`(5)/(3)` ·
`(2)/(1)` =
`(10)/(3)`

k

Multiply h + j + 2k = 16 by 2 ---> 2h + 2j + 4k = 32

Then subtract 2h + 2j + 4k = 32 by 2h + 2j + k = 31

2h + 2j + 4k = 32

-(2h + 2j + k = 31)

3k = 1 Divide both sides by 3 to get k

k = 1