Answer:
Garden A has 42 currant bushes before the transplant
Explanation:
Suppose garden A is x and garden B is y
Forming the linear equations
Garden A has 9 more currant bushes than garden B
Therefore
x=y+9 --------(1)
If 3 currant bushes are transplanted from Garden B to Garden A, then Garden A will have 1.5 times more currant bushes than Garden B.
When 3 currant bushes are transplanted then the new equation becomes
x=y+12--------(2)
Further after transplanting
x+3= 1.5y----------(3)
putting the value of y from equation 2 into equation 3
x+3 = 1.5(x-12)
x+3= 1.5x-18
x-1.5x=-18-3
-0.5x=-21
![x=(21* 10)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rshyet7hn02ea6jan1tb65ivn79nfx7tp6.png)
x=42
Hence garden A has 42 currant bushes before the transplant