Answer: Hello there!
we have the function f(x) = IxI and we want to write the formula represented by the transformation
"First, a vertical stretch with scale factor 3 is performed, then a reflection over the x-axis, then a translation left
4 units, and finally a translation up 5 units."
first, we have a vertical stretch; this means that we have
y = a*f(x) where a is a real number, in this case, the scale is 3, so we have:
y = 3*f(x) = 3IxI
now we have a reflection over the x-axis
this is equivalent to multiply our function for -1.
y = -1(3f(x)) = -3f(x) = -3IxI
Now a translation left for 4 units, this is equivalent to have the change from x to x + 4; this is
y = f(x + 4)
then our function is:
y = -3f(x+4) = -3I x + 4I
Finally a translation up by 5 units.
For this we need to add to te function a constant equal to 5.
y = f(x) + 5
in our case:
y = -3f(x + 4) + 5 = -3Ix+4I + 5
Then our function after all of these trnasformations is:
f(x) = -3Ix+4I + 5