Question

If a gas is initially at 5.50 atm, 121L, 293K,

then it changes to 5.15 atm and 298K, what is the new volume?

Answer 1

New volume is 131.428 liters

Step-by-step explanation:

In the question, we are given;

Initial pressure, P1 = 5.50 atm

Initial volume, V1 = 121 L

Initial temperature, T1 = 293 K

New pressure, P2 = 5.15 atm

New temperature, T2 = 298 K

We are required to find the new volume, V2,

Using the combined gas law, whose formula is ;

`(P1V1)/(T1)=(P2V2)/(T2)`

To get V2

`V2=(P1V1T2)/(T1P2)`

Therefore;

`V2=((5.50)(121)(298))/((293)(5.15))`

`V2=131.428liters`

Thus, the new volume is 131.428 Liters