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Sandra is now three times as old as her daughter .Five years ago her age was 10 years more

2 Answers

7 votes

Explanation:

Aaron (A)=30 years old currently. (Aaron's son (S)=10 years old currently)

PREMISES

3S+10=2(S+10)

ASSUMPTIONS

Let A=Aaron's “current” age (3S in terms of his son's age)

Let S=Aaron's son's “current” age (S)

CALCULATIONS

3S+10=2(S+10)

3S+10=2S+20

(3S-2S)+10=(2S-2S)+20

S+10=0+20

S+(10–10)=20–10

S+0=10

S=

10 years old

and,

if S=10 years old, then

A=3S (Aaron's “current” age in terms of his son's age)

A=3(10)

A=

30 years old

PROOF

If A=30 years old, then the equations

3S+10=2(S+10)

3(10)+10=2(10)+20

30+10=20+20 and

40=40 establish the roots (zeros) A, S={30 years old, 10 years old} of the mathematical statement 3S+10=2(S+10)

User Makerj
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3 votes

Explanation:

This is an incomplete question. Kindly complete it for assistance

User Panky Sharma
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